Dynamically Create and Execute a Batch File Using Visual Studio

Create a directory called “c:\bat”.
Create a directory called “c:\zip”.

Copy some .zip files to “c:\zip”

Create a new Visual Studio C# application.
Add a button to Form1.
Double click on button1 and copy and paste the code below into the Click event.

      
      private void button1_Click(object sender, EventArgs e)
      {
      try
      {
      //This will create a new .bat file in the bat directory.
      System.IO.StreamWriter file = new System.IO.StreamWriter(@"C:\bat\dirlist.bat       //The code below will write lines to the .bat file.
      //The dir command is used in a Command to list files in the specified directory.
      //The > command in this case sends the list to a text file.
      file.WriteLine(@"dir C:\Zip\*.zip > C:\bat\dir.txt");
      file.WriteLine("exit");
      file.Close();

      //The System.Dignostics.Process Process Class allows a Visual Studio Program
      //to execute another application
      System.Diagnostics.Process proc = new System.Diagnostics.Process();

      proc = new System.Diagnostics.Process();

      proc.EnableRaisingEvents = false;
      //This line executes the .bat file created above.
      proc.StartInfo.FileName = @"C:\bat\dirlist.bat";
      proc.Start();
      }
      catch (System.Exception err)
      {
      System.Windows.Forms.MessageBox.Show(err.Message, "Error", MessageBoxButtons.OK, MessageBoxIcon.Error);
      }
      }
      
    

#CSharp #VisualStudio